nilai maksimum f(x) = 4x^2 + 4x + 12

jawaban tertera di pict ^

jawab

f(x) = 4x^2  +  4x  + 12
nilai maksimum, jika f '(x) = 0
8x + 4 = 0
x = -1/2

f(- 1/2) = 4(- 1/2)² + 4 (-1/2)+ 12
f (-1/2) = 4(1/4) - 2 + 12
f(-1/2) = 1 - 2 + 12
f(- 1/2) = 9

nilai maksimum = 9