Persamaan kuadrat X^2+3X+(7m-2)=0 . Mempunyai akar penyelesaian x1 dan x2 . Jika berlaku x1^2+x2^2=89. Tentukan nilai m...?? Tolong ya kak... Beserta caranya..

x1 + x2 = -b/a = -3/1 = -3
x1.x2 = c/a = (7m - 2)/1 = 7m - 2

x1² + x2² = (x1 + x2)² - 2x1.x2 = 89
(-3)² - 2(7m - 2) = 89
9 - 14m + 4 = 89
-14m + 13 = 89
-14m = 89 - 13
-14m = 76
m = 76/-14
m = -5(3/7)